Finite square lattice

In this example, the lattice is finite, with a crystal size of 1000 nm times 1000 nm (40 times 40 unit cells). Otherwise the sample model is the same as in the basic square lattice example.

Real-space model

Scattering intensity

For comparison, scattering intensity with infinite lattice

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#!/usr/bin/env python3
"""
Cylinders forming a finite 2D square lattice
"""
import bornagain as ba
from bornagain import ba_plot as bp, deg, nm


def get_sample():
    """
    A sample with cylinders on a substrate, forming a finite 2D square lattice
    """

    # Materials
    particle_color = (0.86, 0.24, 0.18)
    particle_mat = ba.RefractiveMaterial("Particle", particle_color, 0.0006, 2e-08)
    substrate_color = (0.28, 0.57, 0.82)
    substrate_mat = ba.RefractiveMaterial("Substrate", substrate_color, 6e-06, 2e-08)
    vacuum = ba.Vacuum()

    # Particles
    ff = ba.Cylinder(3*nm, 3*nm)
    particle = ba.Particle(particle_mat, ff)

    # 2D lattice
    lattice = ba.SquareLattice2D(25*nm, 30*deg)
    layout = ba.FiniteCrystal2D(particle, lattice, 1000*nm, 1000*nm)
    layout.setLateralPositionVariance(1*nm)

    # Layers
    layer_1 = ba.Layer(vacuum)
    layer_1.deposit2D(layout)
    layer_2 = ba.Layer(substrate_mat)

    # Sample
    sample = ba.Sample()
    sample.addLayer(layer_1)
    sample.addLayer(layer_2)

    return sample


def get_simulation(sample):
    beam = ba.Beam(1e9, 0.1*nm, 0.2*deg)
    n = 200
    detector = ba.SphericalDetector(n, -2*deg, 2*deg, n, 0, 2*deg)
    simulation = ba.ScatteringSimulation(beam, sample, detector)
    return simulation


if __name__ == '__main__':
    sample = get_sample()
    ba.showSample3D(sample, sample_size=240*nm, seed=0)
    simulation = get_simulation(sample)
    result = simulation.simulate()
    bp.plot_datafield(result, unit_aspect=1)
    bp.plt.show()
auto/Examples/scatter2d/FiniteSquareLattice.py